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41555321993 is a prime number
BaseRepresentation
bin100110101100111000…
…111110010010001001
310222021001200002011202
4212230320332102021
51140101130300433
631031254433545
73000531260153
oct465470762211
9128231602152
1041555321993
1116694994519
1280789628b5
133bc3374433
142022d91ad3
15113330cee8
hex9ace3e489

41555321993 has 2 divisors, whose sum is σ = 41555321994. Its totient is φ = 41555321992.

The previous prime is 41555321959. The next prime is 41555322041. The reversal of 41555321993 is 39912355514.

41555321993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36740072329 + 4815249664 = 191677^2 + 69392^2 .

It is a cyclic number.

It is not a de Polignac number, because 41555321993 - 210 = 41555320969 is a prime.

It is a super-3 number, since 3×415553219933 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (41555321953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20777660996 + 20777660997.

It is an arithmetic number, because the mean of its divisors is an integer number (20777660997).

Almost surely, 241555321993 is an apocalyptic number.

It is an amenable number.

41555321993 is a deficient number, since it is larger than the sum of its proper divisors (1).

41555321993 is an equidigital number, since it uses as much as digits as its factorization.

41555321993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 729000, while the sum is 47.

The spelling of 41555321993 in words is "forty-one billion, five hundred fifty-five million, three hundred twenty-one thousand, nine hundred ninety-three".