Base | Representation |
---|---|
bin | 100110101100111001… |
… | …000001001101110001 |
3 | 10222021001200200122111 |
4 | 212230321001031301 |
5 | 1140101131142001 |
6 | 31031255005321 |
7 | 3000531340156 |
oct | 465471011561 |
9 | 128231620574 |
10 | 41555334001 |
11 | 166949a2545 |
12 | 8078969841 |
13 | 3bc3379a3c |
14 | 2022d9622d |
15 | 1133311851 |
hex | 9ace41371 |
41555334001 has 2 divisors, whose sum is σ = 41555334002. Its totient is φ = 41555334000.
The previous prime is 41555333999. The next prime is 41555334059. The reversal of 41555334001 is 10043355514.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40250390625 + 1304943376 = 200625^2 + 36124^2 .
It is a cyclic number.
It is not a de Polignac number, because 41555334001 - 21 = 41555333999 is a prime.
Together with 41555333999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41555334101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20777667000 + 20777667001.
It is an arithmetic number, because the mean of its divisors is an integer number (20777667001).
Almost surely, 241555334001 is an apocalyptic number.
It is an amenable number.
41555334001 is a deficient number, since it is larger than the sum of its proper divisors (1).
41555334001 is an equidigital number, since it uses as much as digits as its factorization.
41555334001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 41555334001 its reverse (10043355514), we get a palindrome (51598689515).
The spelling of 41555334001 in words is "forty-one billion, five hundred fifty-five million, three hundred thirty-four thousand, one".
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