Base | Representation |
---|---|
bin | 10010111010110111111110… |
… | …01000001100011010101111 |
3 | 12110022102122020020202221212 |
4 | 21131123333020030122233 |
5 | 20423130210343122101 |
6 | 224253120521545035 |
7 | 11522612644161164 |
oct | 1135337710143257 |
9 | 173272566222855 |
10 | 41605333567151 |
11 | 122907a51714a2 |
12 | 47bb48604517b |
13 | 1a2a49b4a09a3 |
14 | a3b9cd29806b |
15 | 4c23b46971bb |
hex | 25d6ff20c6af |
41605333567151 has 2 divisors, whose sum is σ = 41605333567152. Its totient is φ = 41605333567150.
The previous prime is 41605333567129. The next prime is 41605333567159. The reversal of 41605333567151 is 15176533350614.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41605333567151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41605333567151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41605333567159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20802666783575 + 20802666783576.
It is an arithmetic number, because the mean of its divisors is an integer number (20802666783576).
Almost surely, 241605333567151 is an apocalyptic number.
41605333567151 is a deficient number, since it is larger than the sum of its proper divisors (1).
41605333567151 is an equidigital number, since it uses as much as digits as its factorization.
41605333567151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402000, while the sum is 50.
The spelling of 41605333567151 in words is "forty-one trillion, six hundred five billion, three hundred thirty-three million, five hundred sixty-seven thousand, one hundred fifty-one".
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