Base | Representation |
---|---|
bin | 100110110000011110… |
… | …111000101000111001 |
3 | 10222102021002010001222 |
4 | 212300132320220321 |
5 | 1140212042420433 |
6 | 31041250321425 |
7 | 3002162460353 |
oct | 466036705071 |
9 | 128367063058 |
10 | 41615591993 |
11 | 16715a0a238 |
12 | 8094b89275 |
13 | 3c029b7261 |
14 | 202ada00d3 |
15 | 1138765b98 |
hex | 9b07b8a39 |
41615591993 has 2 divisors, whose sum is σ = 41615591994. Its totient is φ = 41615591992.
The previous prime is 41615591957. The next prime is 41615592037. The reversal of 41615591993 is 39919551614.
41615591993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39494805289 + 2120786704 = 198733^2 + 46052^2 .
It is a cyclic number.
It is not a de Polignac number, because 41615591993 - 214 = 41615575609 is a prime.
It is not a weakly prime, because it can be changed into another prime (41615591923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20807795996 + 20807795997.
It is an arithmetic number, because the mean of its divisors is an integer number (20807795997).
Almost surely, 241615591993 is an apocalyptic number.
It is an amenable number.
41615591993 is a deficient number, since it is larger than the sum of its proper divisors (1).
41615591993 is an equidigital number, since it uses as much as digits as its factorization.
41615591993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1312200, while the sum is 53.
The spelling of 41615591993 in words is "forty-one billion, six hundred fifteen million, five hundred ninety-one thousand, nine hundred ninety-three".
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