Base | Representation |
---|---|
bin | 100110110011100011… |
… | …011111000011111001 |
3 | 10222112212001111100222 |
4 | 212303203133003321 |
5 | 1140313241121333 |
6 | 31050331105425 |
7 | 3003356520635 |
oct | 466343370371 |
9 | 128485044328 |
10 | 41667129593 |
11 | 167420101a1 |
12 | 80aa2a2275 |
13 | 3c1059048b |
14 | 2033b77dc5 |
15 | 113d046298 |
hex | 9b38df0f9 |
41667129593 has 2 divisors, whose sum is σ = 41667129594. Its totient is φ = 41667129592.
The previous prime is 41667129503. The next prime is 41667129611. The reversal of 41667129593 is 39592176614.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33332900329 + 8334229264 = 182573^2 + 91292^2 .
It is a cyclic number.
It is not a de Polignac number, because 41667129593 - 214 = 41667113209 is a prime.
It is a super-2 number, since 2×416671295932 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41667129503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20833564796 + 20833564797.
It is an arithmetic number, because the mean of its divisors is an integer number (20833564797).
Almost surely, 241667129593 is an apocalyptic number.
It is an amenable number.
41667129593 is a deficient number, since it is larger than the sum of its proper divisors (1).
41667129593 is an equidigital number, since it uses as much as digits as its factorization.
41667129593 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2449440, while the sum is 53.
The spelling of 41667129593 in words is "forty-one billion, six hundred sixty-seven million, one hundred twenty-nine thousand, five hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •