Base | Representation |
---|---|
bin | 100110110100010110… |
… | …001111001010001011 |
3 | 10222120210002102022111 |
4 | 212310112033022023 |
5 | 1140330142340203 |
6 | 31051524203151 |
7 | 3003610561501 |
oct | 466426171213 |
9 | 128523072274 |
10 | 41680433803 |
11 | 16749577908 |
12 | 80b28394b7 |
13 | 3c1326aca8 |
14 | 203583c671 |
15 | 113e2c326d |
hex | 9b458f28b |
41680433803 has 2 divisors, whose sum is σ = 41680433804. Its totient is φ = 41680433802.
The previous prime is 41680433801. The next prime is 41680433849. The reversal of 41680433803 is 30833408614.
41680433803 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41680433803 - 21 = 41680433801 is a prime.
Together with 41680433801, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41680433801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20840216901 + 20840216902.
It is an arithmetic number, because the mean of its divisors is an integer number (20840216902).
Almost surely, 241680433803 is an apocalyptic number.
41680433803 is a deficient number, since it is larger than the sum of its proper divisors (1).
41680433803 is an equidigital number, since it uses as much as digits as its factorization.
41680433803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 40.
The spelling of 41680433803 in words is "forty-one billion, six hundred eighty million, four hundred thirty-three thousand, eight hundred three".
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