Base | Representation |
---|---|
bin | 111100101100010011101… |
… | …001010011110110100011 |
3 | 112202201102020110200222102 |
4 | 330230103221103312203 |
5 | 1021313140131400424 |
6 | 12512002433401015 |
7 | 610216616131526 |
oct | 74542351236643 |
9 | 15681366420872 |
10 | 4170742840739 |
11 | 136889066a002 |
12 | 57439940916b |
13 | 2433b7911747 |
14 | 105c17902bbd |
15 | 73755b3b7ae |
hex | 3cb13a53da3 |
4170742840739 has 2 divisors, whose sum is σ = 4170742840740. Its totient is φ = 4170742840738.
The previous prime is 4170742840697. The next prime is 4170742840741. The reversal of 4170742840739 is 9370482470714.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4170742840739 is a prime.
It is a super-2 number, since 2×41707428407392 (a number of 26 digits) contains 22 as substring.
Together with 4170742840741, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4170742840769) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2085371420369 + 2085371420370.
It is an arithmetic number, because the mean of its divisors is an integer number (2085371420370).
Almost surely, 24170742840739 is an apocalyptic number.
4170742840739 is a deficient number, since it is larger than the sum of its proper divisors (1).
4170742840739 is an equidigital number, since it uses as much as digits as its factorization.
4170742840739 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9483264, while the sum is 56.
The spelling of 4170742840739 in words is "four trillion, one hundred seventy billion, seven hundred forty-two million, eight hundred forty thousand, seven hundred thirty-nine".
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