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4171138980131 is a prime number
BaseRepresentation
bin111100101100101011010…
…000011101100100100011
3112202202102211212200001202
4330230223100131210203
51021314443034331011
612512110024151415
7610232466224054
oct74545320354443
915682384780052
104171138980131
111368a74238432
1257448a00856b
1324344ba00a56
14105c5438072b
157377a7db23b
hex3cb2b41d923

4171138980131 has 2 divisors, whose sum is σ = 4171138980132. Its totient is φ = 4171138980130.

The previous prime is 4171138980119. The next prime is 4171138980161. The reversal of 4171138980131 is 1310898311714.

4171138980131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4171138980131 - 222 = 4171134785827 is a prime.

It is a super-2 number, since 2×41711389801312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4171138980161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2085569490065 + 2085569490066.

It is an arithmetic number, because the mean of its divisors is an integer number (2085569490066).

Almost surely, 24171138980131 is an apocalyptic number.

4171138980131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4171138980131 is an equidigital number, since it uses as much as digits as its factorization.

4171138980131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 47.

The spelling of 4171138980131 in words is "four trillion, one hundred seventy-one billion, one hundred thirty-eight million, nine hundred eighty thousand, one hundred thirty-one".