Base | Representation |
---|---|
bin | 10011000000001010110011… |
… | …00010110110111101110001 |
3 | 12110221211011112122222011222 |
4 | 21200011121202312331301 |
5 | 20434120231204224131 |
6 | 224512443113314425 |
7 | 11542012512032033 |
oct | 1140053142667561 |
9 | 173854145588158 |
10 | 41787239133041 |
11 | 12350961110516 |
12 | 482a791a05a15 |
13 | 1a4169ab472cc |
14 | a467281a9c53 |
15 | 4c6eae30c87b |
hex | 2601598b6f71 |
41787239133041 has 2 divisors, whose sum is σ = 41787239133042. Its totient is φ = 41787239133040.
The previous prime is 41787239133023. The next prime is 41787239133089. The reversal of 41787239133041 is 14033193278714.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41787239133025 + 16 = 6464305^2 + 4^2 .
It is a cyclic number.
It is not a de Polignac number, because 41787239133041 - 222 = 41787234938737 is a prime.
It is not a weakly prime, because it can be changed into another prime (41787239103041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20893619566520 + 20893619566521.
It is an arithmetic number, because the mean of its divisors is an integer number (20893619566521).
Almost surely, 241787239133041 is an apocalyptic number.
It is an amenable number.
41787239133041 is a deficient number, since it is larger than the sum of its proper divisors (1).
41787239133041 is an equidigital number, since it uses as much as digits as its factorization.
41787239133041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 41787239133041 in words is "forty-one trillion, seven hundred eighty-seven billion, two hundred thirty-nine million, one hundred thirty-three thousand, forty-one".
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