Base | Representation |
---|---|
bin | 10011000000011001010111… |
… | …10001110111101100011011 |
3 | 12110222120100200100201120201 |
4 | 21200030223301313230123 |
5 | 20434232241140011333 |
6 | 224520215220403031 |
7 | 11542410402654145 |
oct | 1140145361675433 |
9 | 173876320321521 |
10 | 41795061250843 |
11 | 1235420553238a |
12 | 48301b5546477 |
13 | 1a42346578494 |
14 | a46c6adabc95 |
15 | 4c72badbc17d |
hex | 26032bc77b1b |
41795061250843 has 2 divisors, whose sum is σ = 41795061250844. Its totient is φ = 41795061250842.
The previous prime is 41795061250841. The next prime is 41795061250949. The reversal of 41795061250843 is 34805216059714.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41795061250843 - 21 = 41795061250841 is a prime.
Together with 41795061250841, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41795061250841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20897530625421 + 20897530625422.
It is an arithmetic number, because the mean of its divisors is an integer number (20897530625422).
It is a 1-persistent number, because it is pandigital, but 2⋅41795061250843 = 83590122501686 is not.
Almost surely, 241795061250843 is an apocalyptic number.
41795061250843 is a deficient number, since it is larger than the sum of its proper divisors (1).
41795061250843 is an equidigital number, since it uses as much as digits as its factorization.
41795061250843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 55.
The spelling of 41795061250843 in words is "forty-one trillion, seven hundred ninety-five billion, sixty-one million, two hundred fifty thousand, eight hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •