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42011251403453 is a prime number
BaseRepresentation
bin10011000110101100000011…
…01101110110101010111101
312111202020101100021101012222
421203112001231312222331
521001303020324402303
6225203411421535125
711564132654643233
oct1143260155665275
9174666340241188
1042011251403453
11124279652058a2
12486608b1144a5
131a5984ab6a8c7
14a534d939c953
154ccc20898938
hex263581b76abd

42011251403453 has 2 divisors, whose sum is σ = 42011251403454. Its totient is φ = 42011251403452.

The previous prime is 42011251403431. The next prime is 42011251403483. The reversal of 42011251403453 is 35430415211024.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23993960079769 + 18017291323684 = 4898363^2 + 4244678^2 .

It is a cyclic number.

It is not a de Polignac number, because 42011251403453 - 210 = 42011251402429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42011251403483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21005625701726 + 21005625701727.

It is an arithmetic number, because the mean of its divisors is an integer number (21005625701727).

Almost surely, 242011251403453 is an apocalyptic number.

It is an amenable number.

42011251403453 is a deficient number, since it is larger than the sum of its proper divisors (1).

42011251403453 is an equidigital number, since it uses as much as digits as its factorization.

42011251403453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 42011251403453 its reverse (35430415211024), we get a palindrome (77441666614477).

The spelling of 42011251403453 in words is "forty-two trillion, eleven billion, two hundred fifty-one million, four hundred three thousand, four hundred fifty-three".