Base | Representation |
---|---|
bin | 10011000110101100000011… |
… | …01101110110101010111101 |
3 | 12111202020101100021101012222 |
4 | 21203112001231312222331 |
5 | 21001303020324402303 |
6 | 225203411421535125 |
7 | 11564132654643233 |
oct | 1143260155665275 |
9 | 174666340241188 |
10 | 42011251403453 |
11 | 124279652058a2 |
12 | 486608b1144a5 |
13 | 1a5984ab6a8c7 |
14 | a534d939c953 |
15 | 4ccc20898938 |
hex | 263581b76abd |
42011251403453 has 2 divisors, whose sum is σ = 42011251403454. Its totient is φ = 42011251403452.
The previous prime is 42011251403431. The next prime is 42011251403483. The reversal of 42011251403453 is 35430415211024.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23993960079769 + 18017291323684 = 4898363^2 + 4244678^2 .
It is a cyclic number.
It is not a de Polignac number, because 42011251403453 - 210 = 42011251402429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42011251403483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21005625701726 + 21005625701727.
It is an arithmetic number, because the mean of its divisors is an integer number (21005625701727).
Almost surely, 242011251403453 is an apocalyptic number.
It is an amenable number.
42011251403453 is a deficient number, since it is larger than the sum of its proper divisors (1).
42011251403453 is an equidigital number, since it uses as much as digits as its factorization.
42011251403453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 42011251403453 its reverse (35430415211024), we get a palindrome (77441666614477).
The spelling of 42011251403453 in words is "forty-two trillion, eleven billion, two hundred fifty-one million, four hundred three thousand, four hundred fifty-three".
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