Base | Representation |
---|---|
bin | 111101001000110011011… |
… | …001010110101111000111 |
3 | 112212122101121222200200212 |
4 | 331020303121112233013 |
5 | 1022313321104101411 |
6 | 12534022531230035 |
7 | 612352062216014 |
oct | 75106331265707 |
9 | 15778347880625 |
10 | 4201340300231 |
11 | 137a862086208 |
12 | 57a2b844831b |
13 | 2462529c2c69 |
14 | 1074bb43270b |
15 | 74446e3068b |
hex | 3d233656bc7 |
4201340300231 has 2 divisors, whose sum is σ = 4201340300232. Its totient is φ = 4201340300230.
The previous prime is 4201340300219. The next prime is 4201340300239. The reversal of 4201340300231 is 1320030431024.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4201340300231 is a prime.
It is a super-2 number, since 2×42013403002312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4201340300197 and 4201340300206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4201340300239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2100670150115 + 2100670150116.
It is an arithmetic number, because the mean of its divisors is an integer number (2100670150116).
Almost surely, 24201340300231 is an apocalyptic number.
4201340300231 is a deficient number, since it is larger than the sum of its proper divisors (1).
4201340300231 is an equidigital number, since it uses as much as digits as its factorization.
4201340300231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4201340300231 its reverse (1320030431024), we get a palindrome (5521370731255).
The spelling of 4201340300231 in words is "four trillion, two hundred one billion, three hundred forty million, three hundred thousand, two hundred thirty-one".
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