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42113415324373 is a prime number
BaseRepresentation
bin10011001001101010010110…
…01010010010001011010101
312112010000002022201021220221
421210311023022102023111
521004441233310334443
6225322345205154341
711604410455643131
oct1144651312221325
9175100068637827
1042113415324373
1112467221068798
124881a416bb9b1
131a6637ca88a13
14a5842b9883c1
154d06eea74eed
hex264d4b2922d5

42113415324373 has 2 divisors, whose sum is σ = 42113415324374. Its totient is φ = 42113415324372.

The previous prime is 42113415324349. The next prime is 42113415324437. The reversal of 42113415324373 is 37342351431124.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24961045186609 + 17152370137764 = 4996103^2 + 4141542^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42113415324373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42113415324073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21056707662186 + 21056707662187.

It is an arithmetic number, because the mean of its divisors is an integer number (21056707662187).

Almost surely, 242113415324373 is an apocalyptic number.

It is an amenable number.

42113415324373 is a deficient number, since it is larger than the sum of its proper divisors (1).

42113415324373 is an equidigital number, since it uses as much as digits as its factorization.

42113415324373 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 725760, while the sum is 43.

Adding to 42113415324373 its reverse (37342351431124), we get a palindrome (79455766755497).

The spelling of 42113415324373 in words is "forty-two trillion, one hundred thirteen billion, four hundred fifteen million, three hundred twenty-four thousand, three hundred seventy-three".