Base | Representation |
---|---|
bin | 111101010011100101011… |
… | …011011100000101110101 |
3 | 112220202021102211100102212 |
4 | 331103211123130011311 |
5 | 1023011023241003433 |
6 | 12543215402543205 |
7 | 613242004500116 |
oct | 75234533340565 |
9 | 15822242740385 |
10 | 4212917125493 |
11 | 138476298339a |
12 | 5805a9507b05 |
13 | 247379290a1b |
14 | 107c98b7620d |
15 | 748c3460d48 |
hex | 3d4e56dc175 |
4212917125493 has 2 divisors, whose sum is σ = 4212917125494. Its totient is φ = 4212917125492.
The previous prime is 4212917125489. The next prime is 4212917125523. The reversal of 4212917125493 is 3945217192124.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2427868818244 + 1785048307249 = 1558162^2 + 1336057^2 .
It is a cyclic number.
It is not a de Polignac number, because 4212917125493 - 22 = 4212917125489 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4212917125393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2106458562746 + 2106458562747.
It is an arithmetic number, because the mean of its divisors is an integer number (2106458562747).
Almost surely, 24212917125493 is an apocalyptic number.
It is an amenable number.
4212917125493 is a deficient number, since it is larger than the sum of its proper divisors (1).
4212917125493 is an equidigital number, since it uses as much as digits as its factorization.
4212917125493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1088640, while the sum is 50.
The spelling of 4212917125493 in words is "four trillion, two hundred twelve billion, nine hundred seventeen million, one hundred twenty-five thousand, four hundred ninety-three".
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