Base | Representation |
---|---|
bin | 100111010101110010… |
… | …001110101100010011 |
3 | 11001000212200110202221 |
4 | 213111302032230103 |
5 | 1143002300420201 |
6 | 31223324121511 |
7 | 3023532101065 |
oct | 472562165423 |
9 | 131025613687 |
10 | 42241420051 |
11 | 16a071a9106 |
12 | 822a696297 |
13 | 3ca2556c0c |
14 | 208a14b735 |
15 | 11736864a1 |
hex | 9d5c8eb13 |
42241420051 has 2 divisors, whose sum is σ = 42241420052. Its totient is φ = 42241420050.
The previous prime is 42241420007. The next prime is 42241420069. The reversal of 42241420051 is 15002414224.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42241420051 - 215 = 42241387283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 42241419998 and 42241420025.
It is not a weakly prime, because it can be changed into another prime (42241420451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21120710025 + 21120710026.
It is an arithmetic number, because the mean of its divisors is an integer number (21120710026).
Almost surely, 242241420051 is an apocalyptic number.
42241420051 is a deficient number, since it is larger than the sum of its proper divisors (1).
42241420051 is an equidigital number, since it uses as much as digits as its factorization.
42241420051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 42241420051 its reverse (15002414224), we get a palindrome (57243834275).
The spelling of 42241420051 in words is "forty-two billion, two hundred forty-one million, four hundred twenty thousand, fifty-one".
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