Base | Representation |
---|---|
bin | 111101011110010011001… |
… | …000000000000010010111 |
3 | 112221211222011202212221022 |
4 | 331132103020000002113 |
5 | 1023203103311400043 |
6 | 12552401115111355 |
7 | 614130044510033 |
oct | 75362310000227 |
9 | 15854864685838 |
10 | 4224421200023 |
11 | 1389626700902 |
12 | 58287a14255b |
13 | 248490768c0b |
14 | 10866a97d1c3 |
15 | 74d483c0868 |
hex | 3d793200097 |
4224421200023 has 2 divisors, whose sum is σ = 4224421200024. Its totient is φ = 4224421200022.
The previous prime is 4224421199993. The next prime is 4224421200047. The reversal of 4224421200023 is 3200021244224.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4224421200023 - 214 = 4224421183639 is a prime.
It is a super-3 number, since 3×42244212000233 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4224421199965 and 4224421200001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4224421200323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2112210600011 + 2112210600012.
It is an arithmetic number, because the mean of its divisors is an integer number (2112210600012).
Almost surely, 24224421200023 is an apocalyptic number.
4224421200023 is a deficient number, since it is larger than the sum of its proper divisors (1).
4224421200023 is an equidigital number, since it uses as much as digits as its factorization.
4224421200023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 26.
Adding to 4224421200023 its reverse (3200021244224), we get a palindrome (7424442444247).
The spelling of 4224421200023 in words is "four trillion, two hundred twenty-four billion, four hundred twenty-one million, two hundred thousand, twenty-three".
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