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42324111433 is a prime number
BaseRepresentation
bin100111011010101101…
…101011000001001001
311001020122021122000201
4213122231223001021
51143134433031213
631235440332201
73025555003612
oct473255530111
9131218248021
1042324111433
1116a4994839a
128252314061
133cb671a326
142097114c09
15117aa6c6dd
hex9dab6b049

42324111433 has 2 divisors, whose sum is σ = 42324111434. Its totient is φ = 42324111432.

The previous prime is 42324111419. The next prime is 42324111437. The reversal of 42324111433 is 33411142324.

It is a happy number.

42324111433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26092587024 + 16231524409 = 161532^2 + 127403^2 .

It is a cyclic number.

It is not a de Polignac number, because 42324111433 - 221 = 42322014281 is a prime.

It is not a weakly prime, because it can be changed into another prime (42324111437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21162055716 + 21162055717.

It is an arithmetic number, because the mean of its divisors is an integer number (21162055717).

Almost surely, 242324111433 is an apocalyptic number.

It is an amenable number.

42324111433 is a deficient number, since it is larger than the sum of its proper divisors (1).

42324111433 is an equidigital number, since it uses as much as digits as its factorization.

42324111433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 28.

Adding to 42324111433 its reverse (33411142324), we get a palindrome (75735253757).

The spelling of 42324111433 in words is "forty-two billion, three hundred twenty-four million, one hundred eleven thousand, four hundred thirty-three".