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4233130013417 is a prime number
BaseRepresentation
bin111101100110011010001…
…101011111001011101001
3112222200110002221110000112
4331212122031133023221
51023323422240412132
613000401215144105
7614555623266404
oct75463215371351
915880402843015
104233130013417
111392295598248
125844aa815035
1324924aab5b36
14108c55436d3b
15751a7c2eab2
hex3d99a35f2e9

4233130013417 has 2 divisors, whose sum is σ = 4233130013418. Its totient is φ = 4233130013416.

The previous prime is 4233130013407. The next prime is 4233130013447. The reversal of 4233130013417 is 7143100313324.

4233130013417 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3697048318441 + 536081694976 = 1922771^2 + 732176^2 .

It is a cyclic number.

It is not a de Polignac number, because 4233130013417 - 24 = 4233130013401 is a prime.

It is not a weakly prime, because it can be changed into another prime (4233130013407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565006708 + 2116565006709.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565006709).

Almost surely, 24233130013417 is an apocalyptic number.

It is an amenable number.

4233130013417 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233130013417 is an equidigital number, since it uses as much as digits as its factorization.

4233130013417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 32.

The spelling of 4233130013417 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, thirteen thousand, four hundred seventeen".