Base | Representation |
---|---|
bin | 111101100110011010001… |
… | …101100011110100101111 |
3 | 112222200110002222102002202 |
4 | 331212122031203310233 |
5 | 1023323422242014211 |
6 | 13000401215412115 |
7 | 614555623406006 |
oct | 75463215436457 |
9 | 15880402872082 |
10 | 4233130032431 |
11 | 1392295600563 |
12 | 5844aa82403b |
13 | 24924aac16a1 |
14 | 108c5543dc3d |
15 | 751a7c3553b |
hex | 3d99a363d2f |
4233130032431 has 2 divisors, whose sum is σ = 4233130032432. Its totient is φ = 4233130032430.
The previous prime is 4233130032317. The next prime is 4233130032499. The reversal of 4233130032431 is 1342300313324.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4233130032431 is a prime.
It is a super-2 number, since 2×42331300324312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4233130032394 and 4233130032403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4233130032631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565016215 + 2116565016216.
It is an arithmetic number, because the mean of its divisors is an integer number (2116565016216).
Almost surely, 24233130032431 is an apocalyptic number.
4233130032431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4233130032431 is an equidigital number, since it uses as much as digits as its factorization.
4233130032431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4233130032431 its reverse (1342300313324), we get a palindrome (5575430345755).
The spelling of 4233130032431 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, thirty-two thousand, four hundred thirty-one".
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