Base | Representation |
---|---|
bin | 110000001000001110100101… |
… | …1101111001101101111110111 |
3 | 2001111221020002022100020221222 |
4 | 1200100131023233031233313 |
5 | 420442024100401224421 |
6 | 4100213122135100555 |
7 | 155112354632132366 |
oct | 14020351357155767 |
9 | 2044836068306858 |
10 | 423343312133111 |
11 | 112987988186337 |
12 | 3b59292a81175b |
13 | 1522b1454b25c6 |
14 | 7677cd5d257dd |
15 | 33e21e754bcab |
hex | 181074bbcdbf7 |
423343312133111 has 2 divisors, whose sum is σ = 423343312133112. Its totient is φ = 423343312133110.
The previous prime is 423343312133051. The next prime is 423343312133149. The reversal of 423343312133111 is 111331213343324.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 423343312133111 - 218 = 423343311870967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (423343312133191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211671656066555 + 211671656066556.
It is an arithmetic number, because the mean of its divisors is an integer number (211671656066556).
Almost surely, 2423343312133111 is an apocalyptic number.
423343312133111 is a deficient number, since it is larger than the sum of its proper divisors (1).
423343312133111 is an equidigital number, since it uses as much as digits as its factorization.
423343312133111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46656, while the sum is 35.
Adding to 423343312133111 its reverse (111331213343324), we get a palindrome (534674525476435).
The spelling of 423343312133111 in words is "four hundred twenty-three trillion, three hundred forty-three billion, three hundred twelve million, one hundred thirty-three thousand, one hundred eleven".
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