423343312133141 has 4 divisors (see below), whose sum is σ = 423346179547392. Its totient is φ = 423340444718892.

The previous prime is 423343312133111. The next prime is 423343312133149. The reversal of 423343312133141 is 141331213343324.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-423343312133141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 423343312133095 and 423343312133104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (423343312133149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1433485655 + ... + 1433780948.

It is an arithmetic number, because the mean of its divisors is an integer number (105836544886848).

Almost surely, 2^{423343312133141} is an apocalyptic number.

It is an amenable number.

423343312133141 is a deficient number, since it is larger than the sum of its proper divisors (2867414251).

423343312133141 is a wasteful number, since it uses less digits than its factorization.

423343312133141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2867414250.

The product of its digits is 186624, while the sum is 38.

Adding to 423343312133141 its reverse (141331213343324), we get a palindrome (564674525476465).

The spelling of 423343312133141 in words is "four hundred twenty-three trillion, three hundred forty-three billion, three hundred twelve million, one hundred thirty-three thousand, one hundred forty-one".