Base | Representation |
---|---|
bin | 1100010101110011011… |
… | …00011010010100110011 |
3 | 1111112110211121200201121 |
4 | 12022321230122110303 |
5 | 23421344142102011 |
6 | 522443151443111 |
7 | 42430444264024 |
oct | 6127154322463 |
9 | 1445424550647 |
10 | 424022222131 |
11 | 153910543442 |
12 | 6a218226497 |
13 | 30ca6418371 |
14 | 16746744c4b |
15 | b06a828e71 |
hex | 62b9b1a533 |
424022222131 has 2 divisors, whose sum is σ = 424022222132. Its totient is φ = 424022222130.
The previous prime is 424022222119. The next prime is 424022222149. The reversal of 424022222131 is 131222220424.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 424022222131 - 27 = 424022222003 is a prime.
It is a super-2 number, since 2×4240222221312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 424022222096 and 424022222105.
It is not a weakly prime, because it can be changed into another prime (424022222111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 212011111065 + 212011111066.
It is an arithmetic number, because the mean of its divisors is an integer number (212011111066).
Almost surely, 2424022222131 is an apocalyptic number.
424022222131 is a deficient number, since it is larger than the sum of its proper divisors (1).
424022222131 is an equidigital number, since it uses as much as digits as its factorization.
424022222131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 424022222131 its reverse (131222220424), we get a palindrome (555244442555).
The spelling of 424022222131 in words is "four hundred twenty-four billion, twenty-two million, two hundred twenty-two thousand, one hundred thirty-one".
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