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4240412140933 is a prime number
BaseRepresentation
bin111101101101001100010…
…000100110010110000101
3120000101020121112212000001
4331231030100212112011
51023433331002002213
613004003552321301
7615234236330023
oct75551420462605
916011217485001
104240412140933
111395392119451
125859a1543231
13249b3b69c927
14109346633713
15754821c71dd
hex3db4c426585

4240412140933 has 2 divisors, whose sum is σ = 4240412140934. Its totient is φ = 4240412140932.

The previous prime is 4240412140891. The next prime is 4240412141027. The reversal of 4240412140933 is 3390412140424.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2990056555684 + 1250355585249 = 1729178^2 + 1118193^2 .

It is a cyclic number.

It is not a de Polignac number, because 4240412140933 - 213 = 4240412132741 is a prime.

It is a super-2 number, since 2×42404121409332 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4240412140892 and 4240412140901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4240412180933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2120206070466 + 2120206070467.

It is an arithmetic number, because the mean of its divisors is an integer number (2120206070467).

Almost surely, 24240412140933 is an apocalyptic number.

It is an amenable number.

4240412140933 is a deficient number, since it is larger than the sum of its proper divisors (1).

4240412140933 is an equidigital number, since it uses as much as digits as its factorization.

4240412140933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 37.

The spelling of 4240412140933 in words is "four trillion, two hundred forty billion, four hundred twelve million, one hundred forty thousand, nine hundred thirty-three".