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424321130113 is a prime number
BaseRepresentation
bin1100010110010111000…
…00101001111010000001
31111120020200001210101121
412023023200221322001
523423002202130423
6522532550232241
742441034044616
oct6131340517201
91446220053347
10424321130113
11153a54241431
126a2a0355681
13310233230aa
141677431250d
15b086bbe45d
hex62cb829e81

424321130113 has 2 divisors, whose sum is σ = 424321130114. Its totient is φ = 424321130112.

The previous prime is 424321130089. The next prime is 424321130131. The reversal of 424321130113 is 311031123424.

Together with next prime (424321130131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 324634434289 + 99686695824 = 569767^2 + 315732^2 .

It is a cyclic number.

It is not a de Polignac number, because 424321130113 - 217 = 424320999041 is a prime.

It is not a weakly prime, because it can be changed into another prime (424321130713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 212160565056 + 212160565057.

It is an arithmetic number, because the mean of its divisors is an integer number (212160565057).

Almost surely, 2424321130113 is an apocalyptic number.

It is an amenable number.

424321130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

424321130113 is an equidigital number, since it uses as much as digits as its factorization.

424321130113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 424321130113 its reverse (311031123424), we get a palindrome (735352253537).

The spelling of 424321130113 in words is "four hundred twenty-four billion, three hundred twenty-one million, one hundred thirty thousand, one hundred thirteen".