Base | Representation |
---|---|
bin | 111101101111111001001… |
… | …010111101011011100111 |
3 | 120000122201210020220112012 |
4 | 331233321022331123213 |
5 | 1024010301124332444 |
6 | 13005203502344435 |
7 | 615366153261611 |
oct | 75577112753347 |
9 | 16018653226465 |
10 | 4243313120999 |
11 | 13966406a7737 |
12 | 586470b8b11b |
13 | 24a1b16c4794 |
14 | 10953da21db1 |
15 | 755a1c0bb9e |
hex | 3dbf92bd6e7 |
4243313120999 has 2 divisors, whose sum is σ = 4243313121000. Its totient is φ = 4243313120998.
The previous prime is 4243313120983. The next prime is 4243313121023. The reversal of 4243313120999 is 9990213133424.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4243313120999 - 24 = 4243313120983 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4243313120909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2121656560499 + 2121656560500.
It is an arithmetic number, because the mean of its divisors is an integer number (2121656560500).
Almost surely, 24243313120999 is an apocalyptic number.
4243313120999 is a deficient number, since it is larger than the sum of its proper divisors (1).
4243313120999 is an equidigital number, since it uses as much as digits as its factorization.
4243313120999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 4243313120999 in words is "four trillion, two hundred forty-three billion, three hundred thirteen million, one hundred twenty thousand, nine hundred ninety-nine".
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