Search a number
-
+
42444020131 is a prime number
BaseRepresentation
bin100111100001110111…
…000101100110100011
311001112222220121211121
4213201313011212203
51143411132121011
631255402353111
73031542134632
oct474167054643
9131488817747
1042444020131
11170005a7597
1282864bb797
134005511816
1420a9009519
151186355e71
hex9e1dc59a3

42444020131 has 2 divisors, whose sum is σ = 42444020132. Its totient is φ = 42444020130.

The previous prime is 42444020111. The next prime is 42444020137. The reversal of 42444020131 is 13102044424.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42444020131 - 235 = 8084281763 is a prime.

It is a super-2 number, since 2×424440201312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42444020096 and 42444020105.

It is not a weakly prime, because it can be changed into another prime (42444020137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21222010065 + 21222010066.

It is an arithmetic number, because the mean of its divisors is an integer number (21222010066).

Almost surely, 242444020131 is an apocalyptic number.

42444020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

42444020131 is an equidigital number, since it uses as much as digits as its factorization.

42444020131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 42444020131 its reverse (13102044424), we get a palindrome (55546064555).

The spelling of 42444020131 in words is "forty-two billion, four hundred forty-four million, twenty thousand, one hundred thirty-one".