Base | Representation |
---|---|
bin | 10011010011110000001001… |
… | …11111110001001001010011 |
3 | 12120100011000111111210212121 |
4 | 21221320010333301021103 |
5 | 21031131321402412431 |
6 | 230145525323035111 |
7 | 11641433421300235 |
oct | 1151700477611123 |
9 | 176304014453777 |
10 | 42460130513491 |
11 | 12590270817aa9 |
12 | 491908396ba97 |
13 | 1a8cc85c62762 |
14 | a6b11d076255 |
15 | 4d9743526611 |
hex | 269e04ff1253 |
42460130513491 has 2 divisors, whose sum is σ = 42460130513492. Its totient is φ = 42460130513490.
The previous prime is 42460130513461. The next prime is 42460130513597. The reversal of 42460130513491 is 19431503106424.
42460130513491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42460130513491 - 215 = 42460130480723 is a prime.
It is not a weakly prime, because it can be changed into another prime (42460130513441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21230065256745 + 21230065256746.
It is an arithmetic number, because the mean of its divisors is an integer number (21230065256746).
Almost surely, 242460130513491 is an apocalyptic number.
42460130513491 is a deficient number, since it is larger than the sum of its proper divisors (1).
42460130513491 is an equidigital number, since it uses as much as digits as its factorization.
42460130513491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 42460130513491 in words is "forty-two trillion, four hundred sixty billion, one hundred thirty million, five hundred thirteen thousand, four hundred ninety-one".
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