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42460130513597 is a prime number
BaseRepresentation
bin10011010011110000001001…
…11111110001001010111101
312120100011000111111211000112
421221320010333301022331
521031131321402413342
6230145525323035405
711641433421300446
oct1151700477611275
9176304014454015
1042460130513597
1112590270818095
12491908396bb65
131a8cc85c62814
14a6b11d0762cd
154d9743526682
hex269e04ff12bd

42460130513597 has 2 divisors, whose sum is σ = 42460130513598. Its totient is φ = 42460130513596.

The previous prime is 42460130513491. The next prime is 42460130513627. The reversal of 42460130513597 is 79531503106424.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33776624038756 + 8683506474841 = 5811766^2 + 2946779^2 .

It is a cyclic number.

It is not a de Polignac number, because 42460130513597 - 218 = 42460130251453 is a prime.

It is a super-3 number, since 3×424601305135973 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42460130593597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21230065256798 + 21230065256799.

It is an arithmetic number, because the mean of its divisors is an integer number (21230065256799).

Almost surely, 242460130513597 is an apocalyptic number.

It is an amenable number.

42460130513597 is a deficient number, since it is larger than the sum of its proper divisors (1).

42460130513597 is an equidigital number, since it uses as much as digits as its factorization.

42460130513597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2721600, while the sum is 50.

The spelling of 42460130513597 in words is "forty-two trillion, four hundred sixty billion, one hundred thirty million, five hundred thirteen thousand, five hundred ninety-seven".