Base | Representation |
---|---|
bin | 10011010100111110101101… |
… | …01001001001010111111011 |
3 | 12120111011212112112220211102 |
4 | 21222133112221021113323 |
5 | 21032324203420120233 |
6 | 230221142131122015 |
7 | 11644455451303205 |
oct | 1152372651112773 |
9 | 176434775486742 |
10 | 42502302504443 |
11 | 125a7141804a91 |
12 | 492529314330b |
13 | 1a93c46cba962 |
14 | a6d19dcad775 |
15 | 4da8b0a461e8 |
hex | 26a7d6a495fb |
42502302504443 has 2 divisors, whose sum is σ = 42502302504444. Its totient is φ = 42502302504442.
The previous prime is 42502302504427. The next prime is 42502302504451. The reversal of 42502302504443 is 34440520320524.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42502302504443 - 24 = 42502302504427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 42502302504397 and 42502302504406.
It is not a weakly prime, because it can be changed into another prime (42502302504143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21251151252221 + 21251151252222.
It is an arithmetic number, because the mean of its divisors is an integer number (21251151252222).
Almost surely, 242502302504443 is an apocalyptic number.
42502302504443 is a deficient number, since it is larger than the sum of its proper divisors (1).
42502302504443 is an equidigital number, since it uses as much as digits as its factorization.
42502302504443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 460800, while the sum is 38.
Adding to 42502302504443 its reverse (34440520320524), we get a palindrome (76942822824967).
The spelling of 42502302504443 in words is "forty-two trillion, five hundred two billion, three hundred two million, five hundred four thousand, four hundred forty-three".
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