Base | Representation |
---|---|
bin | 1100011000100110100… |
… | …11000000000101100111 |
3 | 1111200100121022122200201 |
4 | 12030103103000011213 |
5 | 23432434012314003 |
6 | 523252252251331 |
7 | 42512630105662 |
oct | 6142323000547 |
9 | 1450317278621 |
10 | 425525510503 |
11 | 15451206a225 |
12 | 6a577770b47 |
13 | 311859bc302 |
14 | 1684a2626d9 |
15 | b1077c2b1d |
hex | 63134c0167 |
425525510503 has 2 divisors, whose sum is σ = 425525510504. Its totient is φ = 425525510502.
The previous prime is 425525510471. The next prime is 425525510533. The reversal of 425525510503 is 305015525524.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 425525510503 - 25 = 425525510471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (425525510533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 212762755251 + 212762755252.
It is an arithmetic number, because the mean of its divisors is an integer number (212762755252).
Almost surely, 2425525510503 is an apocalyptic number.
425525510503 is a deficient number, since it is larger than the sum of its proper divisors (1).
425525510503 is an equidigital number, since it uses as much as digits as its factorization.
425525510503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150000, while the sum is 37.
The spelling of 425525510503 in words is "four hundred twenty-five billion, five hundred twenty-five million, five hundred ten thousand, five hundred three".
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