Search a number
-
+
42554040041 is a prime number
BaseRepresentation
bin100111101000011010…
…110001111011101001
311001211122221012210002
4213220122301323221
51144122313240131
631314332432345
73034346241452
oct475032617351
9131748835702
1042554040041
1117057712137
1282b73186b5
134022252c66
1420b9888129
151190d396cb
hex9e86b1ee9

42554040041 has 2 divisors, whose sum is σ = 42554040042. Its totient is φ = 42554040040.

The previous prime is 42554040007. The next prime is 42554040043. The reversal of 42554040041 is 14004045524.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31842618025 + 10711422016 = 178445^2 + 103496^2 .

It is a cyclic number.

It is not a de Polignac number, because 42554040041 - 214 = 42554023657 is a prime.

It is a super-2 number, since 2×425540400412 (a number of 22 digits) contains 22 as substring.

Together with 42554040043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 42554039986 and 42554040013.

It is not a weakly prime, because it can be changed into another prime (42554040043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21277020020 + 21277020021.

It is an arithmetic number, because the mean of its divisors is an integer number (21277020021).

Almost surely, 242554040041 is an apocalyptic number.

It is an amenable number.

42554040041 is a deficient number, since it is larger than the sum of its proper divisors (1).

42554040041 is an equidigital number, since it uses as much as digits as its factorization.

42554040041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12800, while the sum is 29.

Adding to 42554040041 its reverse (14004045524), we get a palindrome (56558085565).

The spelling of 42554040041 in words is "forty-two billion, five hundred fifty-four million, forty thousand, forty-one".