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426050437 is a prime number
BaseRepresentation
bin11001011001010…
…000001110000101
31002200200121022211
4121121100032011
51333032103222
6110135423421
713362240361
oct3131201605
91080617284
10426050437
111a9548aaa
12ba824b71
136a362967
14408262a1
152760c277
hex19650385

426050437 has 2 divisors, whose sum is σ = 426050438. Its totient is φ = 426050436.

The previous prime is 426050423. The next prime is 426050473. The reversal of 426050437 is 734050624.

Together with next prime (426050473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 326669476 + 99380961 = 18074^2 + 9969^2 .

It is a cyclic number.

It is not a de Polignac number, because 426050437 - 27 = 426050309 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 426050399 and 426050408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (426050237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 213025218 + 213025219.

It is an arithmetic number, because the mean of its divisors is an integer number (213025219).

Almost surely, 2426050437 is an apocalyptic number.

It is an amenable number.

426050437 is a deficient number, since it is larger than the sum of its proper divisors (1).

426050437 is an equidigital number, since it uses as much as digits as its factorization.

426050437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 31.

The square root of 426050437 is about 20640.9892447043. The cubic root of 426050437 is about 752.4662145293.

The spelling of 426050437 in words is "four hundred twenty-six million, fifty thousand, four hundred thirty-seven".