Base | Representation |
---|---|
bin | 110000011100011110100010… |
… | …1001011110111101010101111 |
3 | 2001212210021120101011120120211 |
4 | 1200320331011023313222233 |
5 | 421323123221244342033 |
6 | 4110143423310323251 |
7 | 155520416655240622 |
oct | 14070750513675257 |
9 | 2055707511146524 |
10 | 426126341012143 |
11 | 113860191457502 |
12 | 3b9621814b9527 |
13 | 153a07069a1915 |
14 | 77328a6c17db9 |
15 | 343e7cd94b2cd |
hex | 1838f452f7aaf |
426126341012143 has 2 divisors, whose sum is σ = 426126341012144. Its totient is φ = 426126341012142.
The previous prime is 426126341012077. The next prime is 426126341012149. The reversal of 426126341012143 is 341210143621624.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-426126341012143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 426126341012096 and 426126341012105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (426126341012149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 213063170506071 + 213063170506072.
It is an arithmetic number, because the mean of its divisors is an integer number (213063170506072).
Almost surely, 2426126341012143 is an apocalyptic number.
426126341012143 is a deficient number, since it is larger than the sum of its proper divisors (1).
426126341012143 is an equidigital number, since it uses as much as digits as its factorization.
426126341012143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 40.
Adding to 426126341012143 its reverse (341210143621624), we get a palindrome (767336484633767).
The spelling of 426126341012143 in words is "four hundred twenty-six trillion, one hundred twenty-six billion, three hundred forty-one million, twelve thousand, one hundred forty-three".
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