Base | Representation |
---|---|
bin | 10011011000011010110001… |
… | …01011100111001100111111 |
3 | 12120220110211022201111012211 |
4 | 21230031120223213030333 |
5 | 21041243134231242413 |
6 | 230351321425441251 |
7 | 11656140304116202 |
oct | 1154153053471477 |
9 | 176813738644184 |
10 | 42620448305983 |
11 | 12642259a57389 |
12 | 4944165aa0227 |
13 | 1aa2124cb9872 |
14 | a74baac71939 |
15 | 4dd9c7d3983d |
hex | 26c358ae733f |
42620448305983 has 2 divisors, whose sum is σ = 42620448305984. Its totient is φ = 42620448305982.
The previous prime is 42620448305959. The next prime is 42620448306077. The reversal of 42620448305983 is 38950384402624.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42620448305983 - 29 = 42620448305471 is a prime.
It is a super-2 number, since 2×426204483059832 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42620448305783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21310224152991 + 21310224152992.
It is an arithmetic number, because the mean of its divisors is an integer number (21310224152992).
Almost surely, 242620448305983 is an apocalyptic number.
42620448305983 is a deficient number, since it is larger than the sum of its proper divisors (1).
42620448305983 is an equidigital number, since it uses as much as digits as its factorization.
42620448305983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39813120, while the sum is 58.
The spelling of 42620448305983 in words is "forty-two trillion, six hundred twenty billion, four hundred forty-eight million, three hundred five thousand, nine hundred eighty-three".
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