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426985107713 is a prime number
BaseRepresentation
bin1100011011010100100…
…10111011000100000001
31111211010022210212122122
412031222102323010001
523443431141421323
6524053152414025
742564042350303
oct6155222730401
91454108725578
10426985107713
111550a0a6420a
126a904547315
13313592065b8
1416948049973
15b1909daec8
hex636a4bb101

426985107713 has 2 divisors, whose sum is σ = 426985107714. Its totient is φ = 426985107712.

The previous prime is 426985107709. The next prime is 426985107751. The reversal of 426985107713 is 317701589624.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 405841621249 + 21143486464 = 637057^2 + 145408^2 .

It is a cyclic number.

It is not a de Polignac number, because 426985107713 - 22 = 426985107709 is a prime.

It is not a weakly prime, because it can be changed into another prime (426985107793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 213492553856 + 213492553857.

It is an arithmetic number, because the mean of its divisors is an integer number (213492553857).

It is a 2-persistent number, because it is pandigital, and so is 2⋅426985107713 = 853970215426, but 3⋅426985107713 = 1280955323139 is not.

Almost surely, 2426985107713 is an apocalyptic number.

It is an amenable number.

426985107713 is a deficient number, since it is larger than the sum of its proper divisors (1).

426985107713 is an equidigital number, since it uses as much as digits as its factorization.

426985107713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 426985107713 in words is "four hundred twenty-six billion, nine hundred eighty-five million, one hundred seven thousand, seven hundred thirteen".