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4281154560013 is a prime number
BaseRepresentation
bin111110010011001000101…
…100100110000000001101
3120011021102000121012000111
4332103020230212000031
51030120301031410023
613034422452000021
7621206000223652
oct76231054460015
916137360535014
104281154560013
11140069a159981
12591872000011
132509324c4206
1410b2cd65bc29
1576568e6000d
hex3e4c8b2600d

4281154560013 has 2 divisors, whose sum is σ = 4281154560014. Its totient is φ = 4281154560012.

The previous prime is 4281154559987. The next prime is 4281154560071. The reversal of 4281154560013 is 3100654511824.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4176963112644 + 104191447369 = 2043762^2 + 322787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4281154560013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4281154560073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2140577280006 + 2140577280007.

It is an arithmetic number, because the mean of its divisors is an integer number (2140577280007).

Almost surely, 24281154560013 is an apocalyptic number.

It is an amenable number.

4281154560013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4281154560013 is an equidigital number, since it uses as much as digits as its factorization.

4281154560013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 40.

The spelling of 4281154560013 in words is "four trillion, two hundred eighty-one billion, one hundred fifty-four million, five hundred sixty thousand, thirteen".