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42817115441 is a prime number
BaseRepresentation
bin100111111000000110…
…010101010100110001
311002111222221211101102
4213320012111110301
51200142140143231
631400411214145
73044022322232
oct477006252461
9132458854342
1042817115441
1117182166621
12836b447355
1340648c2c89
1421027a9089
1511a8ea2acb
hex9f8195531

42817115441 has 2 divisors, whose sum is σ = 42817115442. Its totient is φ = 42817115440.

The previous prime is 42817115293. The next prime is 42817115447. The reversal of 42817115441 is 14451171824.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36661143841 + 6155971600 = 191471^2 + 78460^2 .

It is a cyclic number.

It is not a de Polignac number, because 42817115441 - 218 = 42816853297 is a prime.

It is a super-3 number, since 3×428171154413 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42817115395 and 42817115404.

It is not a weakly prime, because it can be changed into another prime (42817115447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21408557720 + 21408557721.

It is an arithmetic number, because the mean of its divisors is an integer number (21408557721).

Almost surely, 242817115441 is an apocalyptic number.

It is an amenable number.

42817115441 is a deficient number, since it is larger than the sum of its proper divisors (1).

42817115441 is an equidigital number, since it uses as much as digits as its factorization.

42817115441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 35840, while the sum is 38.

The spelling of 42817115441 in words is "forty-two billion, eight hundred seventeen million, one hundred fifteen thousand, four hundred forty-one".