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42824236448017 is a prime number
BaseRepresentation
bin10011011110010110010110…
…11001101011100100010001
312121121221211200001201200001
421233023023121223210101
521103113014012314032
6231025103240530001
712006643333544113
oct1157131331534421
9177557750051601
1042824236448017
111271072505a782
12497775a180901
131ab84010809ab
14a809c00b93b3
154e3e53b363e7
hex26f2cb66b911

42824236448017 has 2 divisors, whose sum is σ = 42824236448018. Its totient is φ = 42824236448016.

The previous prime is 42824236447981. The next prime is 42824236448053. The reversal of 42824236448017 is 71084463242824.

It is a balanced prime because it is at equal distance from previous prime (42824236447981) and next prime (42824236448053).

It can be written as a sum of positive squares in only one way, i.e., 25737926441536 + 17086310006481 = 5073256^2 + 4133559^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42824236448017 is a prime.

It is not a weakly prime, because it can be changed into another prime (42824236448057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21412118224008 + 21412118224009.

It is an arithmetic number, because the mean of its divisors is an integer number (21412118224009).

Almost surely, 242824236448017 is an apocalyptic number.

It is an amenable number.

42824236448017 is a deficient number, since it is larger than the sum of its proper divisors (1).

42824236448017 is an equidigital number, since it uses as much as digits as its factorization.

42824236448017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16515072, while the sum is 55.

The spelling of 42824236448017 in words is "forty-two trillion, eight hundred twenty-four billion, two hundred thirty-six million, four hundred forty-eight thousand, seventeen".