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42850710317693 is a prime number
BaseRepresentation
bin10011011111000111101010…
…10111011110101001111101
312121201111011200022122120202
421233203311113132221331
521104031223320131233
6231045202231453245
712011601355662455
oct1157436527365175
9177644150278522
1042850710317693
111272097a949913
124980908227225
131abaa5ca5a935
14a81db20c2d65
154e49a2de0be8
hex26f8f55dea7d

42850710317693 has 2 divisors, whose sum is σ = 42850710317694. Its totient is φ = 42850710317692.

The previous prime is 42850710317641. The next prime is 42850710317699. The reversal of 42850710317693 is 39671301705824.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28361557360249 + 14489152957444 = 5325557^2 + 3806462^2 .

It is a cyclic number.

It is not a de Polignac number, because 42850710317693 - 212 = 42850710313597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42850710317699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21425355158846 + 21425355158847.

It is an arithmetic number, because the mean of its divisors is an integer number (21425355158847).

It is a 1-persistent number, because it is pandigital, but 2⋅42850710317693 = 85701420635386 is not.

Almost surely, 242850710317693 is an apocalyptic number.

It is an amenable number.

42850710317693 is a deficient number, since it is larger than the sum of its proper divisors (1).

42850710317693 is an equidigital number, since it uses as much as digits as its factorization.

42850710317693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 56.

The spelling of 42850710317693 in words is "forty-two trillion, eight hundred fifty billion, seven hundred ten million, three hundred seventeen thousand, six hundred ninety-three".