Base | Representation |
---|---|
bin | 1100100000111100100… |
… | …10111010101101010101 |
3 | 1112002220210021120010112 |
4 | 12100132102322231111 |
5 | 24021122240131031 |
6 | 525312551332405 |
7 | 43031632144055 |
oct | 6203622725525 |
9 | 1462823246115 |
10 | 430005005141 |
11 | 156400684908 |
12 | 6b407981105 |
13 | 3171aa6665a |
14 | 16b53151565 |
15 | b2babb062b |
hex | 641e4bab55 |
430005005141 has 2 divisors, whose sum is σ = 430005005142. Its totient is φ = 430005005140.
The previous prime is 430005005081. The next prime is 430005005153. The reversal of 430005005141 is 141500500034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 396580024516 + 33424980625 = 629746^2 + 182825^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-430005005141 is a prime.
It is a super-2 number, since 2×4300050051412 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (430005005641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215002502570 + 215002502571.
It is an arithmetic number, because the mean of its divisors is an integer number (215002502571).
Almost surely, 2430005005141 is an apocalyptic number.
It is an amenable number.
430005005141 is a deficient number, since it is larger than the sum of its proper divisors (1).
430005005141 is an equidigital number, since it uses as much as digits as its factorization.
430005005141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 430005005141 its reverse (141500500034), we get a palindrome (571505505175).
The spelling of 430005005141 in words is "four hundred thirty billion, five million, five thousand, one hundred forty-one".
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