Base | Representation |
---|---|
bin | 110000111000101100111000… |
… | …0011010011010001100001111 |
3 | 2002101112010011011212101111101 |
4 | 1201301121300122122030033 |
5 | 422330202100424242033 |
6 | 4122313432540203531 |
7 | 156400603132200514 |
oct | 14161316032321417 |
9 | 2071463134771441 |
10 | 430005421712143 |
11 | 11501630337a292 |
12 | 40289b218395a7 |
13 | 155c244ccbc9a4 |
14 | 7828532aad30b |
15 | 34aa663db097d |
hex | 187167069a30f |
430005421712143 has 2 divisors, whose sum is σ = 430005421712144. Its totient is φ = 430005421712142.
The previous prime is 430005421712137. The next prime is 430005421712159. The reversal of 430005421712143 is 341217124500034.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 430005421712143 - 213 = 430005421703951 is a prime.
It is a super-5 number, since 5×4300054217121435 (a number of 74 digits) contains 55555 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (430005421712743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215002710856071 + 215002710856072.
It is an arithmetic number, because the mean of its divisors is an integer number (215002710856072).
Almost surely, 2430005421712143 is an apocalyptic number.
430005421712143 is a deficient number, since it is larger than the sum of its proper divisors (1).
430005421712143 is an equidigital number, since it uses as much as digits as its factorization.
430005421712143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 37.
The spelling of 430005421712143 in words is "four hundred thirty trillion, five billion, four hundred twenty-one million, seven hundred twelve thousand, one hundred forty-three".
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