43001113013 has 2 divisors, whose sum is σ = 43001113014. Its totient is φ = 43001113012.

The previous prime is 43001112937. The next prime is 43001113021. The reversal of 43001113013 is 31031110034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39108226564 + 3892886449 = 197758^2 + 62393^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43001113013 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 43001112982 and 43001113000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43001116013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21500556506 + 21500556507.

It is an arithmetic number, because the mean of its divisors is an integer number (21500556507).

Almost surely, 2^43001113013 is an apocalyptic number.

It is an amenable number.

43001113013 is a deficient number, since it is larger than the sum of its proper divisors (1).

43001113013 is an equidigital number, since it uses as much as digits as its factorization.

43001113013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 43001113013 its reverse (31031110034), we get a palindrome (74032223047).

The spelling of 43001113013 in words is "forty-three billion, one million, one hundred thirteen thousand, thirteen".