Base | Representation |
---|---|
bin | 101000000011000100… |
… | …100111001000000001 |
3 | 11002222211100222100212 |
4 | 220003010213020001 |
5 | 1201031302312231 |
6 | 31430545123505 |
7 | 3051416166134 |
oct | 500304471001 |
9 | 132884328325 |
10 | 43001213441 |
11 | 1726707812a |
12 | 8401029595 |
13 | 4093aa01c4 |
14 | 211d00c21b |
15 | 11ba21a42b |
hex | a03127201 |
43001213441 has 2 divisors, whose sum is σ = 43001213442. Its totient is φ = 43001213440.
The previous prime is 43001213407. The next prime is 43001213443. The reversal of 43001213441 is 14431210034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37682574400 + 5318639041 = 194120^2 + 72929^2 .
It is a cyclic number.
It is not a de Polignac number, because 43001213441 - 222 = 42997019137 is a prime.
Together with 43001213443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (43001213443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21500606720 + 21500606721.
It is an arithmetic number, because the mean of its divisors is an integer number (21500606721).
Almost surely, 243001213441 is an apocalyptic number.
It is an amenable number.
43001213441 is a deficient number, since it is larger than the sum of its proper divisors (1).
43001213441 is an equidigital number, since it uses as much as digits as its factorization.
43001213441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 43001213441 its reverse (14431210034), we get a palindrome (57432423475).
The spelling of 43001213441 in words is "forty-three billion, one million, two hundred thirteen thousand, four hundred forty-one".
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