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430114122313 is a prime number
BaseRepresentation
bin1100100001001001100…
…11001010101001001001
31112010012101121021202021
412100210303022221021
524021333203403223
6525331450204441
743034425500661
oct6204463125111
91463171537667
10430114122313
11156457233197
126b438423721
133173754cc25
1416b638371a1
15b2c556665d
hex6424ccaa49

430114122313 has 2 divisors, whose sum is σ = 430114122314. Its totient is φ = 430114122312.

The previous prime is 430114122233. The next prime is 430114122337. The reversal of 430114122313 is 313221411034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 340947384649 + 89166737664 = 583907^2 + 298608^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-430114122313 is a prime.

It is not a weakly prime, because it can be changed into another prime (430114182313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215057061156 + 215057061157.

It is an arithmetic number, because the mean of its divisors is an integer number (215057061157).

Almost surely, 2430114122313 is an apocalyptic number.

It is an amenable number.

430114122313 is a deficient number, since it is larger than the sum of its proper divisors (1).

430114122313 is an equidigital number, since it uses as much as digits as its factorization.

430114122313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 430114122313 its reverse (313221411034), we get a palindrome (743335533347).

The spelling of 430114122313 in words is "four hundred thirty billion, one hundred fourteen million, one hundred twenty-two thousand, three hundred thirteen".