Base | Representation |
---|---|
bin | 10011100011110100000111… |
… | …01001111111001010010001 |
3 | 12122021220112000121202210021 |
4 | 21301322003221333022101 |
5 | 21114202044344332144 |
6 | 231251240100103441 |
7 | 12026341510630225 |
oct | 1161720351771221 |
9 | 178256460552707 |
10 | 43012011324049 |
11 | 12783323087339 |
12 | 49a8023694b81 |
13 | 1b000276c55b1 |
14 | a89b146da785 |
15 | 4e8c93bbb884 |
hex | 271e83a7f291 |
43012011324049 has 2 divisors, whose sum is σ = 43012011324050. Its totient is φ = 43012011324048.
The previous prime is 43012011323989. The next prime is 43012011324067. The reversal of 43012011324049 is 94042311021034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25864395347025 + 17147615977024 = 5085705^2 + 4140968^2 .
It is a cyclic number.
It is not a de Polignac number, because 43012011324049 - 27 = 43012011323921 is a prime.
It is not a weakly prime, because it can be changed into another prime (43012011324749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506005662024 + 21506005662025.
It is an arithmetic number, because the mean of its divisors is an integer number (21506005662025).
Almost surely, 243012011324049 is an apocalyptic number.
It is an amenable number.
43012011324049 is a deficient number, since it is larger than the sum of its proper divisors (1).
43012011324049 is an equidigital number, since it uses as much as digits as its factorization.
43012011324049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 34.
The spelling of 43012011324049 in words is "forty-three trillion, twelve billion, eleven million, three hundred twenty-four thousand, forty-nine".
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