Base | Representation |
---|---|
bin | 111110100110100011111… |
… | …001011111010111110101 |
3 | 120020021020121120221112102 |
4 | 332212203321133113311 |
5 | 1030441010034121323 |
6 | 13052152251431445 |
7 | 622544603552555 |
oct | 76464371372765 |
9 | 16207217527472 |
10 | 4302012020213 |
11 | 14095226a5496 |
12 | 595913155585 |
13 | 2528a771c93b |
14 | 10c30b789165 |
15 | 76d8a103328 |
hex | 3e9a3e5f5f5 |
4302012020213 has 2 divisors, whose sum is σ = 4302012020214. Its totient is φ = 4302012020212.
The previous prime is 4302012020177. The next prime is 4302012020227. The reversal of 4302012020213 is 3120202102034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4299514219729 + 2497800484 = 2073527^2 + 49978^2 .
It is a cyclic number.
It is not a de Polignac number, because 4302012020213 - 216 = 4302011954677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4302012020113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2151006010106 + 2151006010107.
It is an arithmetic number, because the mean of its divisors is an integer number (2151006010107).
Almost surely, 24302012020213 is an apocalyptic number.
It is an amenable number.
4302012020213 is a deficient number, since it is larger than the sum of its proper divisors (1).
4302012020213 is an equidigital number, since it uses as much as digits as its factorization.
4302012020213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 4302012020213 its reverse (3120202102034), we get a palindrome (7422214122247).
The spelling of 4302012020213 in words is "four trillion, three hundred two billion, twelve million, twenty thousand, two hundred thirteen".
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