43021002310241 has 2 divisors, whose sum is σ = 43021002310242. Its totient is φ = 43021002310240.

The previous prime is 43021002310147. The next prime is 43021002310243. The reversal of 43021002310241 is 14201320012034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28390407910225 + 14630594400016 = 5328265^2 + 3824996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43021002310241 is a prime.

It is a super-2 number, since 2×43021002310241² (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 43021002310243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (43021002310243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21510501155120 + 21510501155121.

It is an arithmetic number, because the mean of its divisors is an integer number (21510501155121).

Almost surely, 2^{43021002310241} is an apocalyptic number.

It is an amenable number.

43021002310241 is a deficient number, since it is larger than the sum of its proper divisors (1).

43021002310241 is an equidigital number, since it uses as much as digits as its factorization.

43021002310241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 43021002310241 its reverse (14201320012034), we get a palindrome (57222322322275).

The spelling of 43021002310241 in words is "forty-three trillion, twenty-one billion, two million, three hundred ten thousand, two hundred forty-one".