Base | Representation |
---|---|
bin | 1100100001010111101… |
… | …10001011010010010011 |
3 | 1112010111122001222020112 |
4 | 12100223312023102103 |
5 | 24022103440230031 |
6 | 525351312231535 |
7 | 43040362436426 |
oct | 6205366132223 |
9 | 1463448058215 |
10 | 430232351891 |
11 | 156507a45891 |
12 | 6b46bb3b5ab |
13 | 31755ba7064 |
14 | 16b754119bd |
15 | b2d0b1c62b |
hex | 642bd8b493 |
430232351891 has 2 divisors, whose sum is σ = 430232351892. Its totient is φ = 430232351890.
The previous prime is 430232351839. The next prime is 430232351893. The reversal of 430232351891 is 198153232034.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-430232351891 is a prime.
It is a super-2 number, since 2×4302323518912 (a number of 24 digits) contains 22 as substring.
Together with 430232351893, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (430232351893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215116175945 + 215116175946.
It is an arithmetic number, because the mean of its divisors is an integer number (215116175946).
Almost surely, 2430232351891 is an apocalyptic number.
430232351891 is a deficient number, since it is larger than the sum of its proper divisors (1).
430232351891 is an equidigital number, since it uses as much as digits as its factorization.
430232351891 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 430232351891 in words is "four hundred thirty billion, two hundred thirty-two million, three hundred fifty-one thousand, eight hundred ninety-one".
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