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43031959493 is a prime number
BaseRepresentation
bin101000000100111001…
…111001011111000101
311010001222020001000112
4220010321321133011
51201112140200433
631434004122405
73052241422565
oct500471713705
9133058201015
1043031959493
1117282468096
12840b396405
13409a276933
142123132da5
1511bcc90348
hexa04e797c5

43031959493 has 2 divisors, whose sum is σ = 43031959494. Its totient is φ = 43031959492.

The previous prime is 43031959429. The next prime is 43031959511. The reversal of 43031959493 is 39495913034.

43031959493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38503073284 + 4528886209 = 196222^2 + 67297^2 .

It is a cyclic number.

It is not a de Polignac number, because 43031959493 - 26 = 43031959429 is a prime.

It is a super-3 number, since 3×430319594933 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43031959403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21515979746 + 21515979747.

It is an arithmetic number, because the mean of its divisors is an integer number (21515979747).

Almost surely, 243031959493 is an apocalyptic number.

It is an amenable number.

43031959493 is a deficient number, since it is larger than the sum of its proper divisors (1).

43031959493 is an equidigital number, since it uses as much as digits as its factorization.

43031959493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1574640, while the sum is 50.

The spelling of 43031959493 in words is "forty-three billion, thirty-one million, nine hundred fifty-nine thousand, four hundred ninety-three".