43034112019 has 2 divisors, whose sum is σ = 43034112020. Its totient is φ = 43034112018.

The previous prime is 43034111977. The next prime is 43034112047. The reversal of 43034112019 is 91021143034.

It is an a-pointer prime, because the next prime (43034112047) can be obtained adding 43034112019 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43034112019 - 2¹¹ = 43034109971 is a prime.

It is a super-4 number, since 4×43034112019⁴ (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (43034116019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21517056009 + 21517056010.

It is an arithmetic number, because the mean of its divisors is an integer number (21517056010).

Almost surely, 2^43034112019 is an apocalyptic number.

43034112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

43034112019 is an equidigital number, since it uses as much as digits as its factorization.

43034112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 43034112019 in words is "forty-three billion, thirty-four million, one hundred twelve thousand, nineteen".